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4x^2-200x+625=0
a = 4; b = -200; c = +625;
Δ = b2-4ac
Δ = -2002-4·4·625
Δ = 30000
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{30000}=\sqrt{10000*3}=\sqrt{10000}*\sqrt{3}=100\sqrt{3}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-200)-100\sqrt{3}}{2*4}=\frac{200-100\sqrt{3}}{8} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-200)+100\sqrt{3}}{2*4}=\frac{200+100\sqrt{3}}{8} $
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